A batted baseball, which leaves the bat at an angle 〖30〗^0 above the horizontal, is caught by an outfielder 120m from the plate.

a.) What is the initiated velocity of the ball?
b.) How high did it rise?
c.) How long was it in the air?

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.please help me to answer this question. Thanks :)

1 answer

a) The distance the ball travels is
D = Vo^2*sin60/g = 120 m
Solve for the initial velocity Vo

Vo^2 = 120*9.8/sin60 = 1358 m^2/s^2
Vo = 36.85 m/s

b) H = Vo^2sin^2(30)/(2*g)

c) Hang time = 2*Vo*sin30/g