distance = rate x time
speed of sound is 340 m/s (see your later question)
d = 340 x 0.1 = 34 meters.
BUT the sound must travel to the wall of the cave AND back so that makes it 17 m to the wall and 17 m back to the bat.
A bat flying in a cave emits a sound and receives its echo 0.1s later. Show that the distance to the wall of the cave is 17m.
Thanks!
1 answer
1 answer