A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3203 tickets overall. It has sold 267 more​ $20 tickets than​ $10 tickets. The total sales are ​$62,610. How many tickets of each kind have been​ sold?

Answer 1

so, what have they told you?
If there are
x $10 seats
y $20 seats
z $30 seats, then

x+y+z = 3203
y = x+267
10x+20y+30z = 62610

Now just solve as usual for x,y,z
Post your work if you get stuck