A basketball player throws the ball at a 38° angle above the horizontal to a hoop which is located a horizontal distance L = 5.6 m from the point of release and at a height h = 0.4 m above it. What is the required speed if the basketball is to reach the hoop?

Answer 1

Range = Vo^2*sin2A/g = 5.6 m.

Vo^2*sin76/9.8 = 5.6
.099Vo^2 = 5.6
Vo^2 = 56.56
Vo = 7.52 m/s.