a basketball player makes 60% of the free throws that he attempts, except that if he has just tried and missed a free throw then his chances of making a second one go down to only 30%. what is the probability that he makes both attempts? what is the probability that he makes at least one attempt?

Answer 1

To make both: .6 times .6 = .36

Make at least one of two:
1st 2nd
make .6 make .6 miss .4

miss .4 make .3 miss .7

Makes at least one means one or two made

(.6)(.6) + (.6)(.4) + (.4)(.3

multiply and sum and you should get your answer.