a basketball player achieves a hang time of 0.996 s in dunking the ball. What vertical height will he attain?

Answer 1

Hint: He spends 0.498 s coming back down.

H = (g/2) t^2

Use t = 0.498 s

H = 1.21 meters = 3.97 feet

That height applies to his center of mass, relative to where it is when he lands. His outstretched hand, containing the ball, will be much higher above the floor at that time.

Assuming the player's CM is 3 feet above the floor and the ball in the hand is 4 feet above the center of mass, the ball is about 11 feet above the floor at max height, which is sufficient for a dunk.