find the flight time (t)
tan(30º) = 1/2 g t^2 / 4.70 t ... 0 = 4.90 t^2 - [tan(30º) * 4.70 * t]
... solve the quadratic for t
the release height is the squared term ... 4.90 t^2
A basketball is thrown horizontally with an initial speed of 4.70 m/s . A straight line drawn from the release point to the landing point makes an angle of 30.0 with the horizontal. What was the release hight?
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1 answer