A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement.

Question

Calculate the probability of selecting an apple and a banana.
A. 21/190
B. 7/80
C. 7/76
D. 3/5

Answer 1

First, calculate the total number of ways to select 2 fruits from the basket:

Total number of fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Total number of ways to select 2 fruits = 20C2 = (20*19) / (2*1) = 190

Next, calculate the number of ways to select an apple and a banana out of 20 fruits:

Number of ways to select an apple = 7 (apples)
Number of ways to select a banana = 5 (bananas)
Number of ways to select an apple and a banana = 7 * 5 = 35

Now, calculate the probability of selecting an apple and a banana:

Probability = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits
Probability = 35 / 190 = 7 / 38

Therefore, the correct answer is not listed here. The correct answer is 7/38.

Answer 2

What is the possibility of you picking and apple and a bannana in percent form?

Answer 3

To convert the probability of selecting an apple and a banana (7/38) into percent form, you can multiply the probability by 100.

Probability = 7/38
Percentage = (7/38) * 100 = 18.42%

Therefore, the probability of selecting an apple and a banana from the basket is 18.42% in percent form.