To calculate the probability of selecting an apple and a banana, we need to find the probability of selecting first an apple and then a banana, as well as the probability of selecting first a banana and then an apple, and then add these probabilities together.
Probability of selecting an apple first: 7/20
Probability of selecting a banana second: 5/19
Probability of selecting a banana first: 5/20
Probability of selecting an apple second: 7/19
So, the total probability of selecting an apple and a banana is:
(7/20) * (5/19) + (5/20) * (7/19) = 35/380 = 7/76
Therefore, the correct answer is: Start Fraction 7 over 76 End Fraction
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
Responses
35
Start Fraction 3 over 5 End Fraction
21190
Start Fraction 21 over 190 End Fraction
776
Start Fraction 7 over 76 End Fraction
780
7 answers
i thought it was 7/80
I apologize for the confusion. Let's reevaluate:
Probability of selecting an apple first: 7/20
Probability of selecting a banana second: 5/19
Probability of selecting a banana first: 5/20
Probability of selecting an apple second: 7/19
Let's calculate again:
(7/20) * (5/19) + (5/20) * (7/19) = 35/380 = 7/76
Therefore, the correct probability of selecting an apple and a banana is 7/76, not 7/80. Thank you for pointing out the error.
Probability of selecting an apple first: 7/20
Probability of selecting a banana second: 5/19
Probability of selecting a banana first: 5/20
Probability of selecting an apple second: 7/19
Let's calculate again:
(7/20) * (5/19) + (5/20) * (7/19) = 35/380 = 7/76
Therefore, the correct probability of selecting an apple and a banana is 7/76, not 7/80. Thank you for pointing out the error.
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.
To calculate the probability of selecting an apple and a banana, let's first find the total number of ways to select 2 fruits from the basket.
Total number of fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Total number of ways to select 2 fruits from 20 = 20C2 = 190
Now, let's find the number of ways of selecting an apple and a banana:
Number of ways to select 1 apple out of 7 = 7C1 = 7
Number of ways to select 1 banana out of 5 = 5C1 = 5
Number of ways to select 1 apple and 1 banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = Number of ways to select 1 apple and 1 banana / Total number of ways to select 2 fruits
Probability = 35/190 = 7/38
So, the correct answer is 7/38.
Total number of fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Total number of ways to select 2 fruits from 20 = 20C2 = 190
Now, let's find the number of ways of selecting an apple and a banana:
Number of ways to select 1 apple out of 7 = 7C1 = 7
Number of ways to select 1 banana out of 5 = 5C1 = 5
Number of ways to select 1 apple and 1 banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = Number of ways to select 1 apple and 1 banana / Total number of ways to select 2 fruits
Probability = 35/190 = 7/38
So, the correct answer is 7/38.
i calculated either 7/76 or 7/80
Let's reevaluate the calculation:
Number of ways to select 1 apple out of 7 = 7C1 = 7
Number of ways to select 1 banana out of 5 = 5C1 = 5
Number of ways to select 1 apple and 1 banana = 7 * 5 = 35
Total number of ways to select 2 fruits from 20 = 20C2 = 190
Therefore, the probability of selecting an apple and a banana = Number of ways to select 1 apple and 1 banana / Total number of ways to select 2 fruits
Probability = 35/190 = 7/38
It appears there was a mistake in the previous calculations. The correct probability of selecting an apple and a banana is indeed 7/38. Thank you for your patience.
Number of ways to select 1 apple out of 7 = 7C1 = 7
Number of ways to select 1 banana out of 5 = 5C1 = 5
Number of ways to select 1 apple and 1 banana = 7 * 5 = 35
Total number of ways to select 2 fruits from 20 = 20C2 = 190
Therefore, the probability of selecting an apple and a banana = Number of ways to select 1 apple and 1 banana / Total number of ways to select 2 fruits
Probability = 35/190 = 7/38
It appears there was a mistake in the previous calculations. The correct probability of selecting an apple and a banana is indeed 7/38. Thank you for your patience.