To calculate the probability of selecting an apple and a banana, we first need to determine the total number of ways to select 2 fruits out of the total number of fruits in the basket.
Total number of fruits = 5 bananas + 8 mangoes + 7 apples = 20 fruits
Total number of ways to select 2 fruits = 20 choose 2 = 20! / (2! * (20-2)!) = (20 * 19) / (2 * 1) = 190 ways
Next, we need to determine the number of ways to select 1 apple and 1 banana. The number of ways to select 1 apple = 7 and the number of ways to select 1 banana = 5. Therefore, the number of ways to select 1 apple and 1 banana = 7 * 5 = 35 ways.
Finally, the probability of selecting an apple and a banana = Number of ways to select 1 apple and 1 banana / Total number of ways to select 2 fruits = 35 / 190 = 0.1842 ≈ 0.1842
Therefore, the probability of selecting an apple and a banana is approximately 0.1842 or as a fraction 35/190.
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
Responses
21190
Start Fraction 21 over 190 End Fraction
776
Start Fraction 7 over 76 End Fraction
35
Start Fraction 3 over 5 End Fraction
780
1 answer