A basket contains the following pieces of fruit: 10 apples, 7 oranges, and 8 bananas. Jameson picks a fruit at random and does not replace it. Then Brittany picks a fruit at random. What is the probability that Jameson gets a banana and Brittany gets an orange?

1 answer

There are a total of 25 pieces of fruit in the basket.

The probability of Jameson picking a banana is 8/25, as there are 8 bananas out of 25 total fruits in the basket. Once Jameson picks a fruit, there are now 24 fruits left in the basket, including 7 oranges. Therefore, the probability of Brittany picking an orange after Jameson has picked a banana is 7/24.

To find the probability of both events happening (Jameson getting a banana AND Brittany getting an orange), we multiply the probabilities:

P(Jameson gets a banana AND Brittany gets an orange) = (8/25)*(7/24)

Simplifying this expression gives:

P(Jameson gets a banana AND Brittany gets an orange) = 7/75

Therefore, the probability that Jameson gets a banana and Brittany gets an orange is 7/75.