A basket contains 3 red balls 5 blue balls and 7 green balls. Two balls are picked one after the other without replacement find the probability that. (a) Both are red. (b) First is blue, the other is green. (c) One is blue, the other is green. (d) Both are of different colours. (e) They are of the same colours.

Answer 1

a) prob(RR) = (3/15)(2/14) = 1/35

b) Prob(B, then G) = (5/15)(7/14) = 1/6 <---- the order was important

c) Prob( B, G) order not important = P(B,G) + P(G,B) = ....

do e) first
e) prob( same colour) = Prob(R,R) + Prob(G,G) + prob(B,B)
= (3/15)(2/14) + (7/15)(6/14) + (5/15)(4/14) = ....

d) Prob(2 different colours) = 1 - (answer to e) )

Answer 2

I need full answer

Answer 3

Full solution plz

Answer 4

I need the complete solving

I need the complete solving

Answer 5

bag contains 3 blue balls, 5 green balls and 7 red balls, three balls are drawn from the bag one after the other without replacement, find the probability that;one is blue,the other is green

Answer 6

(d) 1/14 + 1/6 + 1/10 = 71/210 not 1/7.