a basket ball was thrown horizontally with an initial speed of 4.20m/s.A straight line drawn from the point of release to the point of landing makes an angle of 30.0° with the horizontal.From what height was the ball released?

1 answer

let t equal time of flight

tan(30º) = 4.20 t / (1/2 * 9.8 * t^2)

solve for t

height = 1/2 * 9.8 * t^2