A baseball traveling upward passes a window 28.0 m above the street with a vertical speed of 13.0 m/s. If the ball was thrown from street level, what is the maximum height that the baseball reaches?

Question

A baseball traveling upward passes a window 28.0 m above the street with a vertical speed of 13.0 m/s.  If the ball was thrown from street level, what is the maximum height that the baseball reaches?

Damon · Answer

v = v i - g t st top v = 0 so t = vi/g to top then h = 28 + vi t - 4.9 t^2