A baseball teams ace pitcher throws fast balls at a velocity of 160kmh, the balls are released at a height of 1.6m from the ground, given that the distance between pitcher and plate is 18.4m how far has the ball dropped when it passes over the plate?

Answer 1

First convert 160 km/h to 44.4 m/s.

Assuming that the initial velocity of the throw is horizontal (which may not be true in practice) the ball drops (1/2) g t^2, where t is the time of flight to home plate, 18.4/44.4 = 0.41 s.

g is the acceleration of gravity, as you know.

You will not need to use the 1.6 meter number to get the answer.