A baseball player pops a pitch straight up. The ball (mass 230g ) was traveling horizontally at 36.0m/s just before contact with the bat, and 21.0m/s just after contact.

Question

Part A
Determine the magnitude of the impulse delivered to the ball by the bat.

Part B
Determine the direction of the impulse delivered to the ball by the bat. Assume the initial direction of the ball as +x-axis direction.
Answer this Question

Answer 1

A. X = 36 m/s.
Y = 21 m/s.

V^2 = X^2 + Y^2 =
V^2 = 36^2 + 21^2 = 1737
V = 41.7 m/s.
Impulse = m*V = 0.23 * 41.7 = 9.59

B. tan A = Y/X = 21/36 = 0.58333
A = 30.3o = Direction.