A baseball player dives into third base with a speed of 7.90 m/s. If the coefficient of friction between the player and the ground is 0.41, how far does the player slide before coming to rest?

2 answers

V^2 = Vo^2 + 2a*d.
V = 0.
Vo = 7.90 m/s.
a = u*g = 0.41 * (-9.8) = -4.02 m/s^2.
d = ?
i need to figure out the answer
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