A baseball pitcher throws a ball with a maximum speed of 150. km/h.

If the ball is thrown horizontally, how far does it fall vertically by the time it reaches the catcher's glove 20. m away? Give your answer numerically in meters using decimal notation (omit the units).

Use the acceleration due to gravity as g=9.8 m/s2

1 answer

Ignoring air resistance (which is considerable in this case of 150 km/h)
Convert the speed into m and s.
150 km/s
= 150000/3600 m/s
=41.667 m/s
Horizontal distance
=20 m
Time required, t
=20/41.678 s
=0.48 s.
The ball was thrown horizontally, so the initial vertical velocity, u=0 m/s
Acceleration, a = -g = -9.8 m/s/s
Vertical distance
=ut + (1/2)at²
=0*0.48 + (1/2)*(-9.8)0.48²
=-1.129 m.

I assume you have a computer to check the answer, so determine the number of decimal places you need to present, 1.1, or 1.13, or 1.129, or in negative (downwards).