A baseball pitcher can throw a baseball at a speed of 42 m/s. If the mass of the ball is 0.12 kg and the pitcher has it in his hand over a distance of 1.9 m, what is the average force exerted by the pitcher on the ball?
3 answers
i already got the answer.
W = F d = (1/2) m v^2
F (1.9) = (1/2) (.12)(42^2)
F (1.9) = (1/2) (.12)(42^2)
f=.5x.12x42^2/1.9