The height of the spectator relative to the ground can be calculated using the equation:
h = (vf^2 - vi^2) / (2 * g)
where h is the height, vf is the final velocity, vi is the initial velocity, and g is the acceleration due to gravity (9.8 m/s^2).
Plugging in the given values, we get:
h = (2.3^2 - 8.2^2) / (2 * 9.8)
h = -7.2 m
Since the height is negative, this means that the spectator is 7.2 m below the ground.
A baseball of mass 0.25 kg is hit so hard that it bounces on the ground and winds up in a spectator’s seat. If the ball leaves the ground at a speed 8.2 m/s and lands in the seat with a speed of 2.3 m/s, at what height, in metres relative to the ground, is the spectator?
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