A baseball is thrown such that it is in the air for 4 seconds and lands 100 m away. Find the initial vertical and horizontal components of the baseball's velocity.

Answer 1

horizontal:
u ( 4 ) = 100
u = 25 m/s^2

vertical in air for 4 seconds
so up for 2 seconds
first up, stops at top
v = Vi - 9.8 t
0 = Vi - 9.8(2)
Vi = 2(9.8) or about 20 m/s^2