YOu know the initial vertical component, and the initial horizontal component.
final height=initialheight+vovertical*time-1/2 g time^2
solve for time...this is time in the air.
Now at max height, vvertical will be zero
0=vovertical-g*time solve for time max height, then use that time in the h equation to determine height.
A baseball is thrown, leaving the baseball player’s hand 6.0 ft about the ground and at a 45 degree angle with respect to the horizon. The initial speed is 80 ft/s. Find the maximum height attained, the length of time the ball stays in the air, and the horizontal distance where the ball hits the ground. (assume air resistance is negligible).
2 answers
0.7