Vo = 24.3 m/s.[29o]
Yo = 24.3*sin29 = 11.8 m/s.
Yf = Yo + g*Tr = 0 at max h.
11.8 - 9.81Tr = 0.
Tr = 1.20 s. = Rise time.
h = Yo*Tr + 0.5g*Tr^2.
g = -9.81 m/s^2.
A baseball is thrown at an angle of 29 degrees relative to the ground at a speed of 24.3 m/s. The ball is caught 51.0463 m from the thrower.
The acceleration due to gravity is 9.81 m/s2
How high is the tallest spot in the ball's path?
Answer in units of m
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