a baseball is batted with a speed of 120 ft/sec at an angle of 37 degrees with the ground. find how long the ball is in the air, how high the ball goes, how far from the plate it is caught, and the components of the velocity of the ball 4 sec after it is hit.
2 answers
Kim, did you find the answers?
Vo = 120Ft/s[37o].
Xo = 120*Cos37 = 95.85 Ft/s.
Yo = 120*sin37 = 72.22 Ft/s.
a. Y = Yo + g*Tr.
0 = 72.22 - 32Tr, Tr = 2.26 s. = Rise time.
Tf = Tr = 2.26 = Fall time.
Tr+Tf = 2.26 + 2.26 = 4.52 s. = Time in air.
b. h = Yo*Tr + 0.5g*Tr^2.
h = 72.22 - 16*2.26^2 = 81.5 Ft.
c. d = Xo*(Tr+Tf) = 95.85 * 4.52 = 433 Ft.
d. Y = Yo + g*t = 72.22 - 32*4 = -55.8 Ft/s, and falling.
V = Xo+Yi = 95.85 - 55.8i.
Xo = 120*Cos37 = 95.85 Ft/s.
Yo = 120*sin37 = 72.22 Ft/s.
a. Y = Yo + g*Tr.
0 = 72.22 - 32Tr, Tr = 2.26 s. = Rise time.
Tf = Tr = 2.26 = Fall time.
Tr+Tf = 2.26 + 2.26 = 4.52 s. = Time in air.
b. h = Yo*Tr + 0.5g*Tr^2.
h = 72.22 - 16*2.26^2 = 81.5 Ft.
c. d = Xo*(Tr+Tf) = 95.85 * 4.52 = 433 Ft.
d. Y = Yo + g*t = 72.22 - 32*4 = -55.8 Ft/s, and falling.
V = Xo+Yi = 95.85 - 55.8i.
3 answers