Vi = 27 sin 45
u = 27 cos 45
h = Vi t - 4.9 t^2
at ground h = 0
0 = Vi t -4.9 t^2 = t (Vi-4.9t)
t = Vi/4.9
then
range = u t
A baseball hit just above the ground leaves the bat at 27 m/s at 45∘ above the horizontal.
How far away does the ball strike the ground?
How much time is the ball in the air?
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