To find the force applied to the baseball, we can use Newton's second law of motion, which states:
\[ F = m \cdot a \]
where:
- \( F \) is the force,
- \( m \) is the mass, and
- \( a \) is the acceleration.
First, we need to convert the mass of the baseball from grams to kilograms, since the SI unit of mass is kilograms.
The mass of the baseball is:
\[ m = 145 , \text{g} = 0.145 , \text{kg} \] (since \( 1 , \text{kg} = 1000 , \text{g} \))
The acceleration is given as:
\[ a = 80 , \text{m/s}^2 \]
Now we can calculate the force:
\[ F = m \cdot a = 0.145 , \text{kg} \cdot 80 , \text{m/s}^2 \]
\[ F = 11.6 , \text{N} \]
So, the force applied to the baseball is 11.6 N.