A base of a solid is the region bounded by y=e^-x, the x axis, the y axis, and the line x=2. Each cross section perpendicular to the x-axis is a square Find the volume of the solid

2 answers

So, each square has base and height e^-x

Thus, the volume, adding up all those thin squares, is

∫[0,2] (e^-x)^2 dx
= ∫[0,2] e^(-2x) dx
let u = 2x, and that becomes
(1/2)∫[0,4] e^-u du
...
so would it be 1/2(1-(1/e^4))