A barket contain 3 red ball,5 blue ball and green ball.two ball are picked one after the other without replacement find the probability that
(a)both are red
(b)one it blue the other is red
(c)both are of different colour
(d)they are of the some colour
(e)the first is blue the other is from red
3 answers
Mathematic
Answer quesion
Funny, you posted this twice, and still didn't say how many green balls there are. Let's say there were g of them.
That means there were N = 8+8 balls in total.
(a) 3/N * 2/(N-1)
(b) 2 * 5/N * 3/(N-1)
(c) ((3-1) + (5-1) + (g-1))/(N-1) = (N-3)/(N-1)
(d) 1 - (c)
(e) (b)/2
That means there were N = 8+8 balls in total.
(a) 3/N * 2/(N-1)
(b) 2 * 5/N * 3/(N-1)
(c) ((3-1) + (5-1) + (g-1))/(N-1) = (N-3)/(N-1)
(d) 1 - (c)
(e) (b)/2