a = (V-V)/t = (44-0)/0.028 = 1571 m/s^2
F = m*a = 0.49 * 1571 = 770 N.
A barefoot field-goal kicker imparts a speed
of 44 m/s to a football initially at rest.
If the football has a mass of 0.49 kg and the
time of contact with the ball is 0.028 s, what
is the magnitude of the force exerted by the
ball on the kicker’s foot?
1 answer