(m * .04) + [(m + 260) * .12] = 133.60
.04 m + .12 m + (.12 * 260) = 133.60
A banker invested money in two investments. The first investment returned 4% simple interest. The second investment returned 12% simple interest. If the second investment had $260.00 more money than the first, and the total interest for both investments was $133.60, find the amount invested in each investment.
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