A ballplayer standing at homeplate hits a baseball that is caught by another player at the same height above the ground from which it was hit. The ball is hit with an initial velocity of 23.0 m/s at an angle of 58.0° above the horizontal.

Question

A ballplayer standing at homeplate hits a baseball that is caught by another player at the same height above the ground from which it was hit. The ball is hit with an initial velocity of 23.0 m/s at an angle of 58.0° above the horizontal.
(a) How high will the ball rise?

(b) How much time will elapse from the time the ball leaves the bat until it reaches the fielder?

(c) At what distance from home plate will the fielder be when he catches the ball?

drwls · Answer

a) It will rise until the vertical velocity component equals zero. If we call that time T,
gT = Vo sin 58

Maximum height
= T * average vertical velocity
= (1/2)*[V sin 58]^2 /g

b) 2*T
c) 2T*Vx = 2*T*Vo cos 58