Based on the given scenario, the ideal gas law can be applied to determine the change in volume. The ideal gas law is represented as PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
Since the pressure is constant, P does not change.
The initial temperature T1 is 150 K, and the final temperature T2 is 300 K.
V1/T1 = V2/T2
Using the above equation, we can solve for V2.
V2 = (V1 * T2) / T1
Since V1 and T1 are both non-zero values, we can determine the relationship between V1 and V2 based on the ratio T2/T1.
If T2 is twice as much as T1 (as in the given scenario), then T2/T1 = 2. Therefore, V2 = 2 * V1.
This implies that the volume doubles (B) when the balloon goes from the very cold freezer at 150 K to the hot car at 300 K.
A balloon under constant pressure goes from a very cold freezer at 150 K to a hot car at 300 K.
A. Volume increases 150 P
B. Volume doubles
C. Volume is cut in half
D. Volume stays the same
1 answer
1 answer