A balloon that contains 0.75 L of air at 25. °C is cooled to -126. °C. The pressure and the number of gas particles do not change. What volume (in L) does the

Question

balloon occupy at -126. °C? Be sure your answer has the correct number of significant figures.

Answer 1

To solve this problem, we can use the combined gas law equation:

(P1)(V1)/(T1) = (P2)(V2)/(T2)

Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure
V2 = final volume
T2 = final temperature

Given:
P1 = P2 (pressure does not change)
V1 = 0.75 L
T1 = 25 °C = 298 K
T2 = -126 °C = 147 K

Plugging in the values, we get:

(1)(0.75)/(298) = (1)(V2)/(147)
0.00251 = V2/147
V2 = 0.00251 x 147
V2 ≈ 0.37 L

Therefore, the balloon occupies approximately 0.37 L at -126. °C.