A balloon is inflated to a volume of 7.0 L on a day when the atmospheric pressure is 765 mmHg. The next day, as a storm front arrives, the atmospheric pressure drops to 725 mmHg. Assuming the temperature remains constant, what is the new volume of the balloon, in liters?

Answer 1

the volume is inversely proportional to the ambient pressure

v = 7.0 L * (765 / 725)