A balloon 150 meters from the observer is rising vertically at constant rate. After 1 minute the angle of elevation is 28 degrees and 29 minutes. What is the angle after 3 minutes?

Answer 1

To figure the height after 1 minute,

h/150 = tan 28°29'

Now, having h, you know that 3h is the altitude after 3 minutes. So, find the angle θ such that

tanθ = 3h/150

Or, in one step,

θ = arctan(3*150*tan28°29')

Answer 2

thanks big help

Answer 3

You're so stupid!!!

Answer 4

tan(28deg59min)= h/150
h= 83.0893 m/min

@3 min
tan(theta)= h(@3min)/150
theta= arctan [(83.0893*3min)/150]
theta= 58.9621 deg

Answer 5

First get the height from its initial position
(Tan28°29') = h / 150
h= 83. 089
Now we will get the angle of the balloon from the observer after 3 mins. (3mins = 3 altitude)

(Tanθ) = (hx3) / 150
(Tanθ) = (83.089x3) / 150
θ = 58.96 deg