A ball was projected horizontally at a speed of

Question

0.52 m s–1 across the top of an inclined board of width
600 mm and length 1200 mm. It reached the bottom
of the board 0.9 s later (Figure 4). Calculate:
a the distance travelled by the ball across the board,
b its acceleration on the board,
c its speed at the bottom of the board.
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I'm stuck on part c, any help would be appreciated! :)

Answer 1

a) S=D/T 0.9 X 0.52 =470mm

Answer 2

S=D/T 0.9 X 0.52 =468mm