It reaches its peak at time 5.80/2 seconds
So then if falls...starting at the top with zero velocity.
h=1/2 g t^2 find h, using t=2.90seconds
A ball thrown straight up takes 5.80 seconds to go up and come back down to its starting point. Neglecting air resistance, how high (in m) does it go?
3 answers
41.209
14