A ball thrown horizontally at vi = 26.0 m/s travels a horizontal distance of d = 51.0 m before hitting the ground. From what height h was the ball thrown?

Answer 1

51/26=1.9615384615384615384615384615385 secs
h(t)=-4.9(t)²+h(h)
h=4.9(1.9615384615384615384615384615385)²
h=18.85m as the initial height
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