To find the height when the ball is moving with a velocity of 12 m/s, we can use the conservation of energy or kinematic equations. Let's use the kinematic equations.
We're assuming the only force acting on the ball is gravity, which means we have a constantly decelerating motion due to the acceleration due to gravity (g), which is approximately 9.81 m/s² downward.
We'll use the following kinematic equation, which relates initial velocity (v_i), final velocity (v_f), acceleration (a), and displacement (s):
v_f^2 = v_i^2 + 2as
Where:
- v_f is the final velocity (12 m/s in this case)
- v_i is the initial velocity (25 m/s in this case)
- a is the acceleration (since it's going upward against gravity, it will be -9.81 m/s²)
- s is the displacement, which is the height we want to find
Plugging in the values we are given:
(12 m/s)² = (25 m/s)² + 2(-9.81 m/s²)s
144 m²/s² = 625 m²/s² - 19.62 m/s² * s
-19.62 m/s² * s = 144 m²/s² - 625 m²/s²
-19.62 m/s² * s = -481 m²/s²
Next, solve for s:
s = -481 m²/s² / -19.62 m/s²
s ≈ 24.52 meters
This means that the ball will be approximately 24.52 meters high when it is moving upward with a velocity of 12 m/s. Note that this is the height relative to the point from which it was thrown.
A ball throw vertically upward with a velocity 25mls find it high when it is moving with velocity of 12m/s
1 answer
1 answer