This ball fell during t=sqrt2h/g) =sqrt(2•0.9/9.8)=0.43 s
Horizontal motion (v(x)=const) =>
L=v(x) •t
v(x)=L/t=2.6/0.43=6.1 m/s
A ball rolls off a tabletop 0.900 m above the floor and lands on the floor 2.60 m away from a point that is directly under the edge of the table. At what speed did the ball roll off of the table?
I would really appreciate it if someone could explain to me how the problem is worked out.
1 answer
1 answer