(A) m g h = 15 m g
(B) m g h = 1/2 m v^2
... v = √(2 g h) = √(30 g)
A ball rolls down a hill which has a vertical height of 15m .ignoring friction, what would be the (A)gravitation potential energy of the ball when it is at the top of the
hill?
(B)velocity of the ball when it reaches the bottom of the hill?
3 answers
I need calculations
Ep =mgh h=15 g=9,8 v=o(15)(9,8)(0)=0