To find the time it takes for the ball to roll up the slope, we can use the kinematic equation:
v^2 = u^2 + 2as
where:
v is the final velocity (0 m/s because the ball comes to a stop)
u is the initial velocity (2.2 m/s)
a is the acceleration (due to gravity, which is -9.81 m/s^2 because the ball is rolling up the slope)
s is the distance the ball moves up the slope (3.2m)
Plugging in the values, we get:
0 = (2.2)^2 + 2(-9.81)(3.2)
0 = 4.84 - 62.784
-57.944 = -62.784
-57.944 / (-62.784) = t^2
t^2 ≈ 0.922
Taking the square root of both sides, we get:
t ≈ √0.922
t ≈ 0.960 s
Therefore, it takes the ball approximately 0.960 seconds to roll up the slope.
a ball rolls 3.2m up a constant slope before it comes to a stop if the initial velocity of the ball was 2.2m/s how long does it take the ball to roll up the slope
1 answer