A ball rolling down a hill was displaced at 19.6m while uniformly accelerating from rest. If the final velocity was 5.00 m/s what was the rate of acceptation?

Answer 1

a = (V^2-Vo^2)/2d
a = (5^2-0)/39.2 = 0.6378 m/s^2.

Answer 2

3.5 m/s root 2