time in air = 3.33
so
time ascending = 3.33/2 = 1.665
v = 0 at top = Vi - 9.81 (1.665)
so
Vi = 16.3 m/s
average speed up = 16.3/2
time up = 1.665
so distance up = 13.6 meters
A ball player catches a ball 3.33s after throwing it vertically upward.
a) with what speed did he throw it?
b) what height did it reach?
1 answer