A ball of mass m = 0.75 kg is thrown straight upward with an initial speed of 8.9 m/s. Plot the gravitational potential energy of the block from its launch height, y = 0, to the height y = 5.0 m. Let U = 0 correspond to y = 0. Determine the turning point (maximum height) of this mass.

Answer 1

Vf^2 = Vo^2 + 2gd = 0.
(8.9)^2 + 2(-9.8)d = 0,
79.21 - 19.6d = 0,
-19.6d = -79.21,
d(max) = -79.21 / -19.6 = 4.04m.