mass irrelevant
78.4 = (1/2) g t^2
t^2 = 2 * 78.4 / 9.81
a ball of mass 5kg is dropped from a height of 78.4m,the time taken by the ball to reach the ground is?
4 answers
S=0.5gt^2
78.5=0.5*10t^2
t=3.96 s
78.5=0.5*10t^2
t=3.96 s
Note to Benson: Nowhere on this planet is the acceleration due to gravity 10m/s^2.
He has a Uranium mine.