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A ball of mass 500g is kicked into the air at angle of 45degree. It reaches a height of 12m. What was it's initial velocity?

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2 g y = (v sin45)^2
solve for v
v = [sqrt(2gy)]/sin45

mgh =1/2mv"2
v"2= 2gh
v"2=2x10,x12
v=15.5

57

21m/s

Excellent. know I need the answer of Kinetic energy and potential energy

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