Use conservation of energy.
vf^2=Vi^2+2gh
vf= sqrt (2*9.8*10)
A ball of mass .3 kg is dropped from a height of 10m. Its momentum when it strikes the ground is?
I know p=mv
how would I find velocity for this problem?
Thanks in advance for your help.
4 answers
potential energy = kinetic energy
mgh=1/2 mv^2
cancel out mass
plug in gravity, height
solve for v
mgh=1/2 mv^2
cancel out mass
plug in gravity, height
solve for v
a ball of mass 5kg is dropped from a height 2meter.
P.e=k.e then,
Mgh=1\2mvsquare
Mgh=1\2mvsquare