A ball of mass 0.7Kg is dropped unto a floor from a height of 5m and rebounds to a height of 3m. Find the impulse on the ball when it hits the floor

Answer 1

impulse=changemomentum
= final momentum-initial

now, the ratio of velocities :

from height 5
mg5=1/2 m v^2
or v=sqrt (10g)
and v to get to height 3 m is
v=sqrt(6g)

impulse=changemomentum=m*(sqrt6g+sqrt3g)

Answer 2

1.5m