A Ball Of Mass 0.25kg Losses Half Of Its Velocity When It Makes A Head On Collision With An Identical Ball Q At Rest.After The Collision,Q Moves off with a speed of 2m/s in the original direction of p.calculate the initial velocity of p.

Answer 1

.25 v = .25 (v/2) + .25 (2)

.125 v = .5

v = 4 m/s

Answer 2

Consider the formula. P=mv. Due to inelastic collisions we concur an impulse logically follows. Impulse = the change of momentum.
Hence in mathematical terms:
(.25)(1/2)V = 0.5(2-V) simplify
0.125V = 1 - 0.5V simplify
0.625V = 1 Simplify
V = 1.6 m/s

Answer 3

Damon is wrong. He forgot to put 1/2*V, I think his logic was that due to the velocity = 2 m/s he automatically assume it was 4 m/s. His mathematics is flawed and you should exempt his answers from your solution sheet. The VELOCITY IS A VARIABLE YOU CANNOT ASSUME BASED UPON THE KINETIC ENERGY THAT FOLLOWS. REMEMBER DUE TO INELASTIC COLLISIONS KINETIC ENERGY IS NOT CONSERVED!!!!!!!!!!!!!!

Answer 4

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Answer 5

Gotta side with Damon on this one. KE is not conserved, but momentum is.

Answer 6

The answer to Richard is 1.2m/s